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201322122143 = 424339474437
BaseRepresentation
bin1011101101111110111…
…0111100101110011111
3201020122111002110010012
42323133232330232133
511244301430402033
6232252555433435
720354643542342
oct2733756745637
9636574073105
10201322122143
11784200a912a
123302645587b
1315ca520147c
149a5b920459
155384584248
hex2edfbbcb9f

201322122143 has 4 divisors (see below), whose sum is σ = 201323020920. Its totient is φ = 201321223368.

The previous prime is 201322122139. The next prime is 201322122163. The reversal of 201322122143 is 341221223102.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 201322122143 - 22 = 201322122139 is a prime.

It is a super-2 number, since 2×2013221221432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201322122163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187121 + ... + 661557.

It is an arithmetic number, because the mean of its divisors is an integer number (50330755230).

Almost surely, 2201322122143 is an apocalyptic number.

201322122143 is a deficient number, since it is larger than the sum of its proper divisors (898777).

201322122143 is an equidigital number, since it uses as much as digits as its factorization.

201322122143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 898776.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 201322122143 its reverse (341221223102), we get a palindrome (542543345245).

The spelling of 201322122143 in words is "two hundred one billion, three hundred twenty-two million, one hundred twenty-two thousand, one hundred forty-three".

Divisors: 1 424339 474437 201322122143