Base | Representation |
---|---|
bin | 11101010010111101111… |
… | …011101011010000100001 |
3 | 21010110111112202002010221 |
4 | 131102331323223100201 |
5 | 230441044143411113 |
6 | 4140510552123041 |
7 | 265310514056410 |
oct | 35227573532041 |
9 | 7113445662127 |
10 | 2013231232033 |
11 | 70689660029a |
12 | 286217096481 |
13 | 117b01807058 |
14 | 6d625c0b477 |
15 | 3757e8a798d |
hex | 1d4bdeeb421 |
2013231232033 has 4 divisors (see below), whose sum is σ = 2300835693760. Its totient is φ = 1725626770308.
The previous prime is 2013231231989. The next prime is 2013231232069. The reversal of 2013231232033 is 3302321323102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a de Polignac number, because none of the positive numbers 2k-2013231232033 is a prime.
It is a super-2 number, since 2×20132312320332 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2013231231989 and 2013231232007.
It is not an unprimeable number, because it can be changed into a prime (2013231232073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143802230853 + ... + 143802230866.
It is an arithmetic number, because the mean of its divisors is an integer number (575208923440).
Almost surely, 22013231232033 is an apocalyptic number.
It is an amenable number.
2013231232033 is a deficient number, since it is larger than the sum of its proper divisors (287604461727).
2013231232033 is an equidigital number, since it uses as much as digits as its factorization.
2013231232033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 287604461726.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 2013231232033 its reverse (3302321323102), we get a palindrome (5315552555135).
The spelling of 2013231232033 in words is "two trillion, thirteen billion, two hundred thirty-one million, two hundred thirty-two thousand, thirty-three".
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