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201324000001 = 336235987687
BaseRepresentation
bin1011101101111111011…
…0000111001100000001
3201020122121121212001111
42323133312013030001
511244302421000001
6232253104003321
720354665523215
oct2733766071401
9636577555044
10201324000001
1178421170a83
1233027000541
1315ca570b127
149a5bc8c945
155384805851
hex2edfd87301

201324000001 has 4 divisors (see below), whose sum is σ = 201330021312. Its totient is φ = 201317978692.

The previous prime is 201323999999. The next prime is 201324000037. The reversal of 201324000001 is 100000423102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100000423102 = 250000211551.

It is a cyclic number.

It is not a de Polignac number, because 201324000001 - 21 = 201323999999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201324000041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2960221 + ... + 3027466.

It is an arithmetic number, because the mean of its divisors is an integer number (50332505328).

Almost surely, 2201324000001 is an apocalyptic number.

It is an amenable number.

201324000001 is a deficient number, since it is larger than the sum of its proper divisors (6021311).

201324000001 is an equidigital number, since it uses as much as digits as its factorization.

201324000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6021310.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 201324000001 its reverse (100000423102), we get a palindrome (301324423103).

The spelling of 201324000001 in words is "two hundred one billion, three hundred twenty-four million, one", and thus it is an aban number.

Divisors: 1 33623 5987687 201324000001