Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000011110000010001 |
3 | 1220222001200111221221 |
4 | 102233333003300101 |
5 | 312212344144213 |
6 | 13125415245041 |
7 | 1311620452660 |
oct | 225777036021 |
9 | 56861614857 |
10 | 20132412433 |
11 | 85a1249491 |
12 | 3a9a379781 |
13 | 1b8ac594a3 |
14 | d8db12dd7 |
15 | 7cc6c438d |
hex | 4affc3c11 |
20132412433 has 8 divisors (see below), whose sum is σ = 23015574720. Its totient is φ = 17251026000.
The previous prime is 20132412431. The next prime is 20132412473. The reversal of 20132412433 is 33421423102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20132412433 - 21 = 20132412431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20132412398 and 20132412407.
It is not an unprimeable number, because it can be changed into a prime (20132412431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 419578 + ... + 465091.
It is an arithmetic number, because the mean of its divisors is an integer number (2876946840).
Almost surely, 220132412433 is an apocalyptic number.
It is an amenable number.
20132412433 is a deficient number, since it is larger than the sum of its proper divisors (2883162287).
20132412433 is an equidigital number, since it uses as much as digits as its factorization.
20132412433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 887927.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 20132412433 its reverse (33421423102), we get a palindrome (53553835535).
The spelling of 20132412433 in words is "twenty billion, one hundred thirty-two million, four hundred twelve thousand, four hundred thirty-three".
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