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20132412433 = 73251884669
BaseRepresentation
bin10010101111111111…
…000011110000010001
31220222001200111221221
4102233333003300101
5312212344144213
613125415245041
71311620452660
oct225777036021
956861614857
1020132412433
1185a1249491
123a9a379781
131b8ac594a3
14d8db12dd7
157cc6c438d
hex4affc3c11

20132412433 has 8 divisors (see below), whose sum is σ = 23015574720. Its totient is φ = 17251026000.

The previous prime is 20132412431. The next prime is 20132412473. The reversal of 20132412433 is 33421423102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20132412433 - 21 = 20132412431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20132412398 and 20132412407.

It is not an unprimeable number, because it can be changed into a prime (20132412431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 419578 + ... + 465091.

It is an arithmetic number, because the mean of its divisors is an integer number (2876946840).

Almost surely, 220132412433 is an apocalyptic number.

It is an amenable number.

20132412433 is a deficient number, since it is larger than the sum of its proper divisors (2883162287).

20132412433 is an equidigital number, since it uses as much as digits as its factorization.

20132412433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 887927.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 20132412433 its reverse (33421423102), we get a palindrome (53553835535).

The spelling of 20132412433 in words is "twenty billion, one hundred thirty-two million, four hundred twelve thousand, four hundred thirty-three".

Divisors: 1 7 3251 22757 884669 6192683 2876058919 20132412433