Search a number
-
+
20133000101113 = 294714771093251
BaseRepresentation
bin1001001001111100101000…
…10100011011110011111001
32122021200210101121200022121
410210332110110123303321
510114324341011213423
6110452550023521241
74145363340152464
oct444762424336371
978250711550277
1020133000101113
1164623a2766579
122311ab0bb9221
13b306c28a6b13
144d8629d582db
1524da8b2ad45d
hex124f9451bcf9

20133000101113 has 8 divisors (see below), whose sum is σ = 21270374282880. Its totient is φ = 19025168106000.

The previous prime is 20133000101107. The next prime is 20133000101147. The reversal of 20133000101113 is 31110100033102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20133000101113 - 29 = 20133000100601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20133000108113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7385545263 + ... + 7385547988.

It is an arithmetic number, because the mean of its divisors is an integer number (2658796785360).

Almost surely, 220133000101113 is an apocalyptic number.

It is an amenable number.

20133000101113 is a deficient number, since it is larger than the sum of its proper divisors (1137374181767).

20133000101113 is a wasteful number, since it uses less digits than its factorization.

20133000101113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14771093327.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 20133000101113 its reverse (31110100033102), we get a palindrome (51243100134215).

The spelling of 20133000101113 in words is "twenty trillion, one hundred thirty-three billion, one hundred one thousand, one hundred thirteen".

Divisors: 1 29 47 1363 14771093251 428361704279 694241382797 20133000101113