Base | Representation |
---|---|
bin | 11101010011000010001… |
… | …001101011010010011010 |
3 | 21010110200110221000200102 |
4 | 131103002021223102122 |
5 | 230441220303323114 |
6 | 4140522001135402 |
7 | 265312333506236 |
oct | 35230211532232 |
9 | 7113613830612 |
10 | 2013302011034 |
11 | 706922553636 |
12 | 28623692a562 |
13 | 117b13389312 |
14 | 6d6313935c6 |
15 | 37585bd92de |
hex | 1d4c226b49a |
2013302011034 has 4 divisors (see below), whose sum is σ = 3019953016554. Its totient is φ = 1006651005516.
The previous prime is 2013302011031. The next prime is 2013302011169. The reversal of 2013302011034 is 4301102033102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1107749935009 + 905552076025 = 1052497^2 + 951605^2 .
It is a junction number, because it is equal to n+sod(n) for n = 2013302010997 and 2013302011015.
It is not an unprimeable number, because it can be changed into a prime (2013302011031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503325502757 + ... + 503325502760.
Almost surely, 22013302011034 is an apocalyptic number.
2013302011034 is a deficient number, since it is larger than the sum of its proper divisors (1006651005520).
2013302011034 is a wasteful number, since it uses less digits than its factorization.
2013302011034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1006651005519.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2013302011034 its reverse (4301102033102), we get a palindrome (6314404044136).
The spelling of 2013302011034 in words is "two trillion, thirteen billion, three hundred two million, eleven thousand, thirty-four".
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