20133111302101 has 4 divisors (see below), whose sum is σ = 23009270059552. Its totient is φ = 17256952544652.

The previous prime is 20133111302099. The next prime is 20133111302111. The reversal of 20133111302101 is 10120311133102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20133111302101 - 2¹ = 20133111302099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20133111302111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438079378715 + ... + 1438079378728.

It is an arithmetic number, because the mean of its divisors is an integer number (5752317514888).

Almost surely, 2^{20133111302101} is an apocalyptic number.

It is an amenable number.

20133111302101 is a deficient number, since it is larger than the sum of its proper divisors (2876158757451).

20133111302101 is an equidigital number, since it uses as much as digits as its factorization.

20133111302101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2876158757450.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 20133111302101 its reverse (10120311133102), we get a palindrome (30253422435203).

The spelling of 20133111302101 in words is "twenty trillion, one hundred thirty-three billion, one hundred eleven million, three hundred two thousand, one hundred one".