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20133120123103 = 131548701547931
BaseRepresentation
bin1001001001111100110110…
…11110010010000011011111
32122021201002202110102112111
410210332123132102003133
510114330112222414403
6110453005552214451
74145366325265021
oct444763336220337
978251082412474
1020133120123103
1164624544928a9
122311b2523a427
13b3071170aa50
144d863bc7c011
1524da96aba56d
hex124f9b7920df

20133120123103 has 4 divisors (see below), whose sum is σ = 21681821671048. Its totient is φ = 18584418575160.

The previous prime is 20133120123097. The next prime is 20133120123143. The reversal of 20133120123103 is 30132102133102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20133120123103 - 241 = 17934096867551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20133120123143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 774350773953 + ... + 774350773978.

It is an arithmetic number, because the mean of its divisors is an integer number (5420455417762).

Almost surely, 220133120123103 is an apocalyptic number.

20133120123103 is a deficient number, since it is larger than the sum of its proper divisors (1548701547945).

20133120123103 is a wasteful number, since it uses less digits than its factorization.

20133120123103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1548701547944.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 20133120123103 its reverse (30132102133102), we get a palindrome (50265222256205).

The spelling of 20133120123103 in words is "twenty trillion, one hundred thirty-three billion, one hundred twenty million, one hundred twenty-three thousand, one hundred three".

Divisors: 1 13 1548701547931 20133120123103