Base | Representation |
---|---|
bin | 11101010011000011001… |
… | …110101110000000110011 |
3 | 21010110201201222112222100 |
4 | 131103003032232000303 |
5 | 230441234422011011 |
6 | 4140523445111443 |
7 | 265312643400261 |
oct | 35230316560063 |
9 | 7113651875870 |
10 | 2013320110131 |
11 | 706931795770 |
12 | 2862409b8583 |
13 | 117b17055445 |
14 | 6d633945431 |
15 | 375875b1d56 |
hex | 1d4c33ae033 |
2013320110131 has 48 divisors (see below), whose sum is σ = 3201861611520. Its totient is φ = 1208929095360.
The previous prime is 2013320110129. The next prime is 2013320110159. The reversal of 2013320110131 is 1310110233102.
2013320110131 is a `hidden beast` number, since 201 + 3 + 320 + 1 + 10 + 131 = 666.
It is not a de Polignac number, because 2013320110131 - 21 = 2013320110129 is a prime.
It is a super-2 number, since 2×20133201101312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2013320110111) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9106780 + ... + 9325238.
It is an arithmetic number, because the mean of its divisors is an integer number (66705450240).
Almost surely, 22013320110131 is an apocalyptic number.
2013320110131 is a deficient number, since it is larger than the sum of its proper divisors (1188541501389).
2013320110131 is a wasteful number, since it uses less digits than its factorization.
2013320110131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219336 (or 219333 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 2013320110131 its reverse (1310110233102), we get a palindrome (3323430343233).
The spelling of 2013320110131 in words is "two trillion, thirteen billion, three hundred twenty million, one hundred ten thousand, one hundred thirty-one".
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