20133312001323 has 4 divisors (see below), whose sum is σ = 26844416001768. Its totient is φ = 13422208000880.

The previous prime is 20133312001241. The next prime is 20133312001381. The reversal of 20133312001323 is 32310021333102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20133312001323 - 2⁴¹ = 17934288745771 is a prime.

It is a super-3 number, since 3×20133312001323³ (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20133312001293 and 20133312001302.

It is not an unprimeable number, because it can be changed into a prime (20133312001223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355552000218 + ... + 3355552000223.

It is an arithmetic number, because the mean of its divisors is an integer number (6711104000442).

Almost surely, 2^{20133312001323} is an apocalyptic number.

20133312001323 is a deficient number, since it is larger than the sum of its proper divisors (6711104000445).

20133312001323 is an equidigital number, since it uses as much as digits as its factorization.

20133312001323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6711104000444.

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 20133312001323 its reverse (32310021333102), we get a palindrome (52443333334425).

The spelling of 20133312001323 in words is "twenty trillion, one hundred thirty-three billion, three hundred twelve million, one thousand, three hundred twenty-three".