Base | Representation |
---|---|
bin | 11101010011000100000… |
… | …000101010010011010011 |
3 | 21010110202122121200211020 |
4 | 131103010000222103103 |
5 | 230441301244432011 |
6 | 4140525033450523 |
7 | 265313162565336 |
oct | 35230400522323 |
9 | 7113678550736 |
10 | 2013333202131 |
11 | 7069391179a9 |
12 | 286245270a43 |
13 | 117b1998a4a4 |
14 | 6d63559261d |
15 | 375887eb006 |
hex | 1d4c402a4d3 |
2013333202131 has 4 divisors (see below), whose sum is σ = 2684444269512. Its totient is φ = 1342222134752.
The previous prime is 2013333202031. The next prime is 2013333202141. The reversal of 2013333202131 is 1312023333102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2013333202131 - 29 = 2013333201619 is a prime.
It is a super-2 number, since 2×20133332021312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2013333202141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335555533686 + ... + 335555533691.
It is an arithmetic number, because the mean of its divisors is an integer number (671111067378).
Almost surely, 22013333202131 is an apocalyptic number.
2013333202131 is a deficient number, since it is larger than the sum of its proper divisors (671111067381).
2013333202131 is an equidigital number, since it uses as much as digits as its factorization.
2013333202131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 671111067380.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 2013333202131 its reverse (1312023333102), we get a palindrome (3325356535233).
The spelling of 2013333202131 in words is "two trillion, thirteen billion, three hundred thirty-three million, two hundred two thousand, one hundred thirty-one".
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