2013402304301 has 4 divisors (see below), whose sum is σ = 2014341831552. Its totient is φ = 2012462777052.

The previous prime is 2013402304279. The next prime is 2013402304351. The reversal of 2013402304301 is 1034032043102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2013402304301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013402304351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469760411 + ... + 469764696.

It is an arithmetic number, because the mean of its divisors is an integer number (503585457888).

Almost surely, 2^{2013402304301} is an apocalyptic number.

It is an amenable number.

2013402304301 is a deficient number, since it is larger than the sum of its proper divisors (939527251).

2013402304301 is an equidigital number, since it uses as much as digits as its factorization.

2013402304301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 939527250.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 2013402304301 its reverse (1034032043102), we get a palindrome (3047434347403).

The spelling of 2013402304301 in words is "two trillion, thirteen billion, four hundred two million, three hundred four thousand, three hundred one".