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201340231421 = 728762890203
BaseRepresentation
bin1011101110000011010…
…0000001111011111101
3201020200202011111101012
42323200310001323331
511244321044401141
6232254443525005
720355253505150
oct2734064017375
9636622144335
10201340231421
117842a34797a
1233030529765
1315ca8ba2114
149a600b5c97
155385e5eceb
hex2ee0d01efd

201340231421 has 4 divisors (see below), whose sum is σ = 230103121632. Its totient is φ = 172577341212.

The previous prime is 201340231387. The next prime is 201340231441. The reversal of 201340231421 is 124132043102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201340231421 - 218 = 201339969277 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201340231441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14381445095 + ... + 14381445108.

It is an arithmetic number, because the mean of its divisors is an integer number (57525780408).

Almost surely, 2201340231421 is an apocalyptic number.

It is an amenable number.

201340231421 is a deficient number, since it is larger than the sum of its proper divisors (28762890211).

201340231421 is an equidigital number, since it uses as much as digits as its factorization.

201340231421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28762890210.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 201340231421 its reverse (124132043102), we get a palindrome (325472274523).

The spelling of 201340231421 in words is "two hundred one billion, three hundred forty million, two hundred thirty-one thousand, four hundred twenty-one".

Divisors: 1 7 28762890203 201340231421