2013403 has 4 divisors (see below), whose sum is σ = 2301040. Its totient is φ = 1725768.

The previous prime is 2013391. The next prime is 2013409. The reversal of 2013403 is 3043102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013403 - 2⁵ = 2013371 is a prime.

It is a plaindrome in base 11.

It is a zygodrome in base 11.

It is not an unprimeable number, because it can be changed into a prime (2013409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143808 + ... + 143821.

It is an arithmetic number, because the mean of its divisors is an integer number (575260).

2^2013403 is an apocalyptic number.

2013403 is a deficient number, since it is larger than the sum of its proper divisors (287637).

2013403 is an equidigital number, since it uses as much as digits as its factorization.

2013403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 287636.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 2013403 is about 1418.9443258987. The cubic root of 2013403 is about 126.2729239816.

Adding to 2013403 its reverse (3043102), we get a palindrome (5056505).

The spelling of 2013403 in words is "two million, thirteen thousand, four hundred three".