201341010442999 has 4 divisors (see below), whose sum is σ = 230104011934864. Its totient is φ = 172578008951136.

The previous prime is 201341010442961. The next prime is 201341010443011. The reversal of 201341010442999 is 999244010143102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201341010442999 - 2¹¹ = 201341010440951 is a prime.

It is a super-2 number, since 2×201341010442999² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201341010442909) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14381500745922 + ... + 14381500745935.

It is an arithmetic number, because the mean of its divisors is an integer number (57526002983716).

Almost surely, 2^{201341010442999} is an apocalyptic number.

201341010442999 is a deficient number, since it is larger than the sum of its proper divisors (28763001491865).

201341010442999 is an equidigital number, since it uses as much as digits as its factorization.

201341010442999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28763001491864.

The product of its (nonzero) digits is 559872, while the sum is 49.

The spelling of 201341010442999 in words is "two hundred one trillion, three hundred forty-one billion, ten million, four hundred forty-two thousand, nine hundred ninety-nine".