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20134101423 = 36711367141
BaseRepresentation
bin10010110000000101…
…100000000110101111
31220222011212022211010
4102300011200012233
5312213312221143
613125515400303
71311641016102
oct226005400657
956864768733
1020134101423
1185a21a2447
123a9aa53093
131b8b3cb1a7
14d90032739
157cc909a33
hex4b01601af

20134101423 has 4 divisors (see below), whose sum is σ = 26845468568. Its totient is φ = 13422734280.

The previous prime is 20134101413. The next prime is 20134101437. The reversal of 20134101423 is 32410143102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 20134101423 - 25 = 20134101391 is a prime.

It is a super-2 number, since 2×201341014232 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20134101423.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20134101413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355683568 + ... + 3355683573.

It is an arithmetic number, because the mean of its divisors is an integer number (6711367142).

Almost surely, 220134101423 is an apocalyptic number.

20134101423 is a deficient number, since it is larger than the sum of its proper divisors (6711367145).

20134101423 is an equidigital number, since it uses as much as digits as its factorization.

20134101423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6711367144.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 20134101423 its reverse (32410143102), we get a palindrome (52544244525).

The spelling of 20134101423 in words is "twenty billion, one hundred thirty-four million, one hundred one thousand, four hundred twenty-three".

Divisors: 1 3 6711367141 20134101423