Base | Representation |
---|---|
bin | 11101010011001000101… |
… | …010111101100110110010 |
3 | 21010110222002202120021211 |
4 | 131103020222331212302 |
5 | 230441431304300424 |
6 | 4140540505510334 |
7 | 265315132344652 |
oct | 35231052754662 |
9 | 7113862676254 |
10 | 2013411400114 |
11 | 706979278234 |
12 | 2862674a23aa |
13 | 117b2cc3959a |
14 | 6d641b0a362 |
15 | 375905e5b94 |
hex | 1d4c8abd9b2 |
2013411400114 has 4 divisors (see below), whose sum is σ = 3020117100174. Its totient is φ = 1006705700056.
The previous prime is 2013411400057. The next prime is 2013411400123. The reversal of 2013411400114 is 4110041143102.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1028023627225 + 985387772889 = 1013915^2 + 992667^2 .
It is a super-2 number, since 2×20134114001142 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503352850027 + ... + 503352850030.
Almost surely, 22013411400114 is an apocalyptic number.
2013411400114 is a deficient number, since it is larger than the sum of its proper divisors (1006705700060).
2013411400114 is a wasteful number, since it uses less digits than its factorization.
2013411400114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1006705700059.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 2013411400114 its reverse (4110041143102), we get a palindrome (6123452543216).
The spelling of 2013411400114 in words is "two trillion, thirteen billion, four hundred eleven million, four hundred thousand, one hundred fourteen".
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