Base | Representation |
---|---|
bin | 10010110000000101… |
… | …100100101010110010 |
3 | 1220222011220021110101 |
4 | 102300011210222302 |
5 | 312213313320424 |
6 | 13125520023014 |
7 | 1311641124433 |
oct | 226005445262 |
9 | 56864807411 |
10 | 20134120114 |
11 | 85a2205499 |
12 | 3a9aa61a6a |
13 | 1b8b406854 |
14 | d9003948a |
15 | 7cc910344 |
hex | 4b0164ab2 |
20134120114 has 8 divisors (see below), whose sum is σ = 30201896988. Its totient is φ = 10066821120.
The previous prime is 20134120109. The next prime is 20134120159. The reversal of 20134120114 is 41102143102.
It can be written as a sum of positive squares in 2 ways, for example, as 18946146025 + 1187974089 = 137645^2 + 34467^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 20134120091 and 20134120100.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17074 + ... + 201394.
Almost surely, 220134120114 is an apocalyptic number.
20134120114 is a deficient number, since it is larger than the sum of its proper divisors (10067776874).
20134120114 is a wasteful number, since it uses less digits than its factorization.
20134120114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238940.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 20134120114 its reverse (41102143102), we get a palindrome (61236263216).
The spelling of 20134120114 in words is "twenty billion, one hundred thirty-four million, one hundred twenty thousand, one hundred fourteen".
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