Base | Representation |
---|---|
bin | 1011101110000011100… |
… | …0011111100101011011 |
3 | 201020200211100221100001 |
4 | 2323200320133211123 |
5 | 11244321344321220 |
6 | 232254524553431 |
7 | 20355266450236 |
oct | 2734070374533 |
9 | 636624327301 |
10 | 201341401435 |
11 | 7842aa76a29 |
12 | 330309b2877 |
13 | 15ca91c1835 |
14 | 9a602dc41d |
15 | 53860e180a |
hex | 2ee0e1f95b |
201341401435 has 16 divisors (see below), whose sum is σ = 259737177600. Its totient is φ = 149348870496.
The previous prime is 201341401423. The next prime is 201341401553. The reversal of 201341401435 is 534104143102.
It is a cyclic number.
It is not a de Polignac number, because 201341401435 - 25 = 201341401403 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22542165 + ... + 22551094.
It is an arithmetic number, because the mean of its divisors is an integer number (16233573600).
Almost surely, 2201341401435 is an apocalyptic number.
201341401435 is a deficient number, since it is larger than the sum of its proper divisors (58395776165).
201341401435 is a wasteful number, since it uses less digits than its factorization.
201341401435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45093330.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 201341401435 its reverse (534104143102), we get a palindrome (735445544537).
The spelling of 201341401435 in words is "two hundred one billion, three hundred forty-one million, four hundred one thousand, four hundred thirty-five".
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