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20134143241 = 107188169563
BaseRepresentation
bin10010110000000101…
…101010010100001001
31220222011221110011221
4102300011222110021
5312213320040431
613125520322041
71311641252032
oct226005522411
956864843157
1020134143241
1185a2220903
123a9aa73321
131b8b414234
14d90043a89
157cc917111
hex4b016a509

20134143241 has 4 divisors (see below), whose sum is σ = 20322312912. Its totient is φ = 19945973572.

The previous prime is 20134143223. The next prime is 20134143251. The reversal of 20134143241 is 14234143102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20134143241 - 25 = 20134143209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20134143251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94084675 + ... + 94084888.

It is an arithmetic number, because the mean of its divisors is an integer number (5080578228).

Almost surely, 220134143241 is an apocalyptic number.

It is an amenable number.

20134143241 is a deficient number, since it is larger than the sum of its proper divisors (188169671).

20134143241 is a wasteful number, since it uses less digits than its factorization.

20134143241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188169670.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 20134143241 its reverse (14234143102), we get a palindrome (34368286343).

The spelling of 20134143241 in words is "twenty billion, one hundred thirty-four million, one hundred forty-three thousand, two hundred forty-one".

Divisors: 1 107 188169563 20134143241