Base | Representation |
---|---|
bin | 1001001001111111010000… |
… | …11011000011001010110011 |
3 | 2122021211102201200221011200 |
4 | 10210333220123003022303 |
5 | 10114340233221340311 |
6 | 110453342030542243 |
7 | 4145443322504163 |
oct | 444775033031263 |
9 | 78254381627150 |
10 | 20134411121331 |
11 | 6462a571a1991 |
12 | 2312225667983 |
13 | b30889013620 |
14 | 4d87214d85a3 |
15 | 24db200cd556 |
hex | 124fe86c32b3 |
20134411121331 has 24 divisors (see below), whose sum is σ = 31320487358160. Its totient is φ = 12390291216576.
The previous prime is 20134411121323. The next prime is 20134411121339. The reversal of 20134411121331 is 13312111443102.
20134411121331 is a `hidden beast` number, since 2 + 0 + 1 + 3 + 4 + 411 + 1 + 213 + 31 = 666.
It is an interprime number because it is at equal distance from previous prime (20134411121323) and next prime (20134411121339).
It is not a de Polignac number, because 20134411121331 - 23 = 20134411121323 is a prime.
It is a super-2 number, since 2×201344111213312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20134411121295 and 20134411121304.
It is not an unprimeable number, because it can be changed into a prime (20134411121339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12763465 + ... + 14253941.
It is an arithmetic number, because the mean of its divisors is an integer number (1305020306590).
Almost surely, 220134411121331 is an apocalyptic number.
20134411121331 is a deficient number, since it is larger than the sum of its proper divisors (11186076236829).
20134411121331 is a wasteful number, since it uses less digits than its factorization.
20134411121331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1605955 (or 1605952 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 20134411121331 its reverse (13312111443102), we get a palindrome (33446522564433).
The spelling of 20134411121331 in words is "twenty trillion, one hundred thirty-four billion, four hundred eleven million, one hundred twenty-one thousand, three hundred thirty-one".
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