Base | Representation |
---|---|
bin | 10010110000000110… |
… | …101110110111101001 |
3 | 1220222012110201100221 |
4 | 102300012232313221 |
5 | 312213403032131 |
6 | 13125530330041 |
7 | 1311643531504 |
oct | 226006566751 |
9 | 56865421327 |
10 | 20134424041 |
11 | 85a23a2876 |
12 | 3a9ab89921 |
13 | 1b8b4b1ca4 |
14 | d900b813b |
15 | 7cc970411 |
hex | 4b01aede9 |
20134424041 has 4 divisors (see below), whose sum is σ = 20147750784. Its totient is φ = 20121097300.
The previous prime is 20134423979. The next prime is 20134424059. The reversal of 20134424041 is 14042443102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20134424041 - 27 = 20134423913 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20134423997 and 20134424015.
It is not an unprimeable number, because it can be changed into a prime (20134424741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6661105 + ... + 6664126.
It is an arithmetic number, because the mean of its divisors is an integer number (5036937696).
Almost surely, 220134424041 is an apocalyptic number.
It is an amenable number.
20134424041 is a deficient number, since it is larger than the sum of its proper divisors (13326743).
20134424041 is a wasteful number, since it uses less digits than its factorization.
20134424041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13326742.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 20134424041 its reverse (14042443102), we get a palindrome (34176867143).
The spelling of 20134424041 in words is "twenty billion, one hundred thirty-four million, four hundred twenty-four thousand, forty-one".
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