Base | Representation |
---|---|
bin | 11101010011001010100… |
… | …001010110010001000011 |
3 | 21010111001021011020221021 |
4 | 131103022201112101003 |
5 | 230442012230342430 |
6 | 4140543535010311 |
7 | 265315660211050 |
oct | 35231241262103 |
9 | 7114037136837 |
10 | 2013442434115 |
11 | 706994844572 |
12 | 286275969997 |
13 | 117b364b40b8 |
14 | 6d645ca8027 |
15 | 375931c607a |
hex | 1d4ca856443 |
2013442434115 has 8 divisors (see below), whose sum is σ = 2761292481120. Its totient is φ = 1380646240512.
The previous prime is 2013442434089. The next prime is 2013442434187. The reversal of 2013442434115 is 5114342443102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2013442434115 - 223 = 2013434045507 is a prime.
It is a super-2 number, since 2×20134424341152 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28763463310 + ... + 28763463379.
It is an arithmetic number, because the mean of its divisors is an integer number (345161560140).
Almost surely, 22013442434115 is an apocalyptic number.
2013442434115 is a deficient number, since it is larger than the sum of its proper divisors (747850047005).
2013442434115 is an equidigital number, since it uses as much as digits as its factorization.
2013442434115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57526926701.
The product of its (nonzero) digits is 46080, while the sum is 34.
Adding to 2013442434115 its reverse (5114342443102), we get a palindrome (7127784877217).
The spelling of 2013442434115 in words is "two trillion, thirteen billion, four hundred forty-two million, four hundred thirty-four thousand, one hundred fifteen".
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