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2013442510115 = 5402688502023
BaseRepresentation
bin11101010011001010100…
…001101000110100100011
321010111001021022010012002
4131103022201220310203
5230442012240310430
64140543540354215
7265315660645451
oct35231241506443
97114037263162
102013442510115
11706994896683
122862759a596b
13117b3650c87a
146d645cc79d1
15375931dd845
hex1d4ca868d23

2013442510115 has 4 divisors (see below), whose sum is σ = 2416131012144. Its totient is φ = 1610754008088.

The previous prime is 2013442510109. The next prime is 2013442510129. The reversal of 2013442510115 is 5110152443102.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013442510115 - 24 = 2013442510099 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201344251007 + ... + 201344251016.

It is an arithmetic number, because the mean of its divisors is an integer number (604032753036).

Almost surely, 22013442510115 is an apocalyptic number.

2013442510115 is a deficient number, since it is larger than the sum of its proper divisors (402688502029).

2013442510115 is an equidigital number, since it uses as much as digits as its factorization.

2013442510115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402688502028.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 2013442510115 its reverse (5110152443102), we get a palindrome (7123594953217).

The spelling of 2013442510115 in words is "two trillion, thirteen billion, four hundred forty-two million, five hundred ten thousand, one hundred fifteen".

Divisors: 1 5 402688502023 2013442510115