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2013493 = 5934127
BaseRepresentation
bin111101011100100110101
310210021222211
413223210311
51003412433
6111053421
723054146
oct7534465
93707884
102013493
111155849
12811271
13556621
143a5acd
1529b8cd
hex1eb935

2013493 has 4 divisors (see below), whose sum is σ = 2047680. Its totient is φ = 1979308.

The previous prime is 2013491. The next prime is 2013511. The reversal of 2013493 is 3943102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013493 - 21 = 2013491 is a prime.

It is a super-2 number, since 2×20134932 = 8108308122098, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17005 + ... + 17122.

It is an arithmetic number, because the mean of its divisors is an integer number (511920).

22013493 is an apocalyptic number.

It is an amenable number.

2013493 is a deficient number, since it is larger than the sum of its proper divisors (34187).

2013493 is an equidigital number, since it uses as much as digits as its factorization.

2013493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34186.

The product of its (nonzero) digits is 648, while the sum is 22.

The square root of 2013493 is about 1418.9760392621. The cubic root of 2013493 is about 126.2748054387.

Adding to 2013493 its reverse (3943102), we get a palindrome (5956595).

The spelling of 2013493 in words is "two million, thirteen thousand, four hundred ninety-three".

Divisors: 1 59 34127 2013493