Base | Representation |
---|---|
bin | 1001001010000010001111… |
… | …11110010110011010010011 |
3 | 2122021222120110012022101021 |
4 | 10211001013332112122103 |
5 | 10114402024114220312 |
6 | 110454205054420311 |
7 | 4145531126522143 |
oct | 445010776263223 |
9 | 78258513168337 |
10 | 20136014210707 |
11 | 64636aa09373a |
12 | 23125b2501697 |
13 | b30a8318b615 |
14 | 4d8834394923 |
15 | 24dbb5bdcc07 |
hex | 125047f96693 |
20136014210707 has 4 divisors (see below), whose sum is σ = 20604293611000. Its totient is φ = 19667734810416.
The previous prime is 20136014210701. The next prime is 20136014210783. The reversal of 20136014210707 is 70701241063102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20136014210707 - 223 = 20136005822099 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20136014210701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234139700082 + ... + 234139700167.
It is an arithmetic number, because the mean of its divisors is an integer number (5151073402750).
Almost surely, 220136014210707 is an apocalyptic number.
20136014210707 is a deficient number, since it is larger than the sum of its proper divisors (468279400293).
20136014210707 is an equidigital number, since it uses as much as digits as its factorization.
20136014210707 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 468279400292.
The product of its (nonzero) digits is 14112, while the sum is 34.
Adding to 20136014210707 its reverse (70701241063102), we get a palindrome (90837255273809).
The spelling of 20136014210707 in words is "twenty trillion, one hundred thirty-six billion, fourteen million, two hundred ten thousand, seven hundred seven".
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