Base | Representation |
---|---|
bin | 11101010011101100011… |
… | …011110110111000111111 |
3 | 21010112111220210202010211 |
4 | 131103230123312320333 |
5 | 230444143410421343 |
6 | 4141120222213251 |
7 | 265336036416505 |
oct | 35235433667077 |
9 | 7115456722124 |
10 | 2014011420223 |
11 | 707156a3a220 |
12 | 2863b4424227 |
13 | 117bc734137a |
14 | 6d69b69a675 |
15 | 375c811979d |
hex | 1d4ec6f6e3f |
2014011420223 has 16 divisors (see below), whose sum is σ = 2201825763072. Its totient is φ = 1826984992000.
The previous prime is 2014011420193. The next prime is 2014011420233. The reversal of 2014011420223 is 3220241104102.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2014011420223 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2014011420194 and 2014011420203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2014011420233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69069615 + ... + 69098767.
It is an arithmetic number, because the mean of its divisors is an integer number (137614110192).
Almost surely, 22014011420223 is an apocalyptic number.
2014011420223 is a deficient number, since it is larger than the sum of its proper divisors (187814342849).
2014011420223 is a wasteful number, since it uses less digits than its factorization.
2014011420223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42446.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 2014011420223 its reverse (3220241104102), we get a palindrome (5234252524325).
The spelling of 2014011420223 in words is "two trillion, fourteen billion, eleven million, four hundred twenty thousand, two hundred twenty-three".
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