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2014011420223 = 114911279129153
BaseRepresentation
bin11101010011101100011…
…011110110111000111111
321010112111220210202010211
4131103230123312320333
5230444143410421343
64141120222213251
7265336036416505
oct35235433667077
97115456722124
102014011420223
11707156a3a220
122863b4424227
13117bc734137a
146d69b69a675
15375c811979d
hex1d4ec6f6e3f

2014011420223 has 16 divisors (see below), whose sum is σ = 2201825763072. Its totient is φ = 1826984992000.

The previous prime is 2014011420193. The next prime is 2014011420233. The reversal of 2014011420223 is 3220241104102.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2014011420223 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2014011420194 and 2014011420203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2014011420233) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69069615 + ... + 69098767.

It is an arithmetic number, because the mean of its divisors is an integer number (137614110192).

Almost surely, 22014011420223 is an apocalyptic number.

2014011420223 is a deficient number, since it is larger than the sum of its proper divisors (187814342849).

2014011420223 is a wasteful number, since it uses less digits than its factorization.

2014011420223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42446.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 2014011420223 its reverse (3220241104102), we get a palindrome (5234252524325).

The spelling of 2014011420223 in words is "two trillion, fourteen billion, eleven million, four hundred twenty thousand, two hundred twenty-three".

Divisors: 1 11 491 5401 12791 29153 140701 320683 6280381 14314123 69084191 157455353 372896023 4101856253 183091947293 2014011420223