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201401420223 = 367133806741
BaseRepresentation
bin1011101110010001110…
…1011100100110111111
3201020212000022012122010
42323210131130212333
511244432230421343
6232304511222303
720356625553153
oct2734435344677
9636760265563
10201401420223
117846093aa33
1233048b17993
1315cb8777203
149a68283063
15538b4e9d33
hex2ee475c9bf

201401420223 has 4 divisors (see below), whose sum is σ = 268535226968. Its totient is φ = 134267613480.

The previous prime is 201401420219. The next prime is 201401420257. The reversal of 201401420223 is 322024104102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 201401420223 - 22 = 201401420219 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 201401420223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201401420203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33566903368 + ... + 33566903373.

It is an arithmetic number, because the mean of its divisors is an integer number (67133806742).

Almost surely, 2201401420223 is an apocalyptic number.

201401420223 is a deficient number, since it is larger than the sum of its proper divisors (67133806745).

201401420223 is an equidigital number, since it uses as much as digits as its factorization.

201401420223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67133806744.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 201401420223 its reverse (322024104102), we get a palindrome (523425524325).

The spelling of 201401420223 in words is "two hundred one billion, four hundred one million, four hundred twenty thousand, two hundred twenty-three".

Divisors: 1 3 67133806741 201401420223