Base | Representation |
---|---|
bin | 11101010011110001111… |
… | …101111111000000010011 |
3 | 21010112202101111002222220 |
4 | 131103301331333000103 |
5 | 230444341142034220 |
6 | 4141133340032123 |
7 | 265341244446402 |
oct | 35236175770023 |
9 | 7115671432886 |
10 | 2014104252435 |
11 | 7071a4385460 |
12 | 28641b532643 |
13 | 117c10645482 |
14 | 6d6a9b43639 |
15 | 375d1355540 |
hex | 1d4f1f7f013 |
2014104252435 has 32 divisors (see below), whose sum is σ = 3517050620160. Its totient is φ = 976112284800.
The previous prime is 2014104252383. The next prime is 2014104252443. The reversal of 2014104252435 is 5342524014102.
It is not a de Polignac number, because 2014104252435 - 29 = 2014104251923 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 2014104252396 and 2014104252405.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2262301 + ... + 3024270.
It is an arithmetic number, because the mean of its divisors is an integer number (109907831880).
Almost surely, 22014104252435 is an apocalyptic number.
2014104252435 is a deficient number, since it is larger than the sum of its proper divisors (1502946367725).
2014104252435 is a wasteful number, since it uses less digits than its factorization.
2014104252435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5288899.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 2014104252435 its reverse (5342524014102), we get a palindrome (7356628266537).
The spelling of 2014104252435 in words is "two trillion, fourteen billion, one hundred four million, two hundred fifty-two thousand, four hundred thirty-five".
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