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201411111023 = 498740387229
BaseRepresentation
bin1011101110010100001…
…0011010100001101111
3201020212200112112220122
42323211002122201233
511244442221023043
6232305455035155
720360104124213
oct2734502324157
9636780475818
10201411111023
1178466359861
123305020babb
1315cba78b105
149a69686943
15538c2b1368
hex2ee509a86f

201411111023 has 4 divisors (see below), whose sum is σ = 201451503240. Its totient is φ = 201370718808.

The previous prime is 201411110969. The next prime is 201411111049. The reversal of 201411111023 is 320111114102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 201411111023 - 232 = 197116143727 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201411110992 and 201411111010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201411110023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20188628 + ... + 20198601.

It is an arithmetic number, because the mean of its divisors is an integer number (50362875810).

Almost surely, 2201411111023 is an apocalyptic number.

201411111023 is a deficient number, since it is larger than the sum of its proper divisors (40392217).

201411111023 is an equidigital number, since it uses as much as digits as its factorization.

201411111023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40392216.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 201411111023 its reverse (320111114102), we get a palindrome (521522225125).

The spelling of 201411111023 in words is "two hundred one billion, four hundred eleven million, one hundred eleven thousand, twenty-three".

Divisors: 1 4987 40387229 201411111023