Base | Representation |
---|---|
bin | 1011101110010100101… |
… | …0000101000010000101 |
3 | 201020212211022121220010 |
4 | 2323211022011002011 |
5 | 11244443224321013 |
6 | 232310010100433 |
7 | 20360130162531 |
oct | 2734512050205 |
9 | 636784277803 |
10 | 201413120133 |
11 | 78467501285 |
12 | 33050a1a719 |
13 | 15cbb012734 |
14 | 9a69a4abc1 |
15 | 538c55b7c3 |
hex | 2ee5285085 |
201413120133 has 4 divisors (see below), whose sum is σ = 268550826848. Its totient is φ = 134275413420.
The previous prime is 201413120131. The next prime is 201413120137. The reversal of 201413120133 is 331021314102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 201413120133 - 21 = 201413120131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201413120131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33568853353 + ... + 33568853358.
It is an arithmetic number, because the mean of its divisors is an integer number (67137706712).
Almost surely, 2201413120133 is an apocalyptic number.
It is an amenable number.
201413120133 is a deficient number, since it is larger than the sum of its proper divisors (67137706715).
201413120133 is an equidigital number, since it uses as much as digits as its factorization.
201413120133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67137706714.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 201413120133 its reverse (331021314102), we get a palindrome (532434434235).
The spelling of 201413120133 in words is "two hundred one billion, four hundred thirteen million, one hundred twenty thousand, one hundred thirty-three".
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