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20141952933 = 36713984311
BaseRepresentation
bin10010110000100011…
…011100111110100101
31220222201122020001210
4102300203130332211
5312222314443213
613130355542033
71312064526564
oct226043347645
956881566053
1020141952933
1185a66753a3
123aa15ba919
131b8cc19b5b
14d910b7bdb
157cd45b0c3
hex4b08dcfa5

20141952933 has 4 divisors (see below), whose sum is σ = 26855937248. Its totient is φ = 13427968620.

The previous prime is 20141952911. The next prime is 20141952949. The reversal of 20141952933 is 33925914102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 20141952933 - 212 = 20141948837 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20141952891 and 20141952900.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20141952533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3356992153 + ... + 3356992158.

It is an arithmetic number, because the mean of its divisors is an integer number (6713984312).

Almost surely, 220141952933 is an apocalyptic number.

It is an amenable number.

20141952933 is a deficient number, since it is larger than the sum of its proper divisors (6713984315).

20141952933 is an equidigital number, since it uses as much as digits as its factorization.

20141952933 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6713984314.

The product of its (nonzero) digits is 58320, while the sum is 39.

The spelling of 20141952933 in words is "twenty billion, one hundred forty-one million, nine hundred fifty-two thousand, nine hundred thirty-three".

Divisors: 1 3 6713984311 20141952933