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2014230131241 = 3671410043747
BaseRepresentation
bin11101010011111001011…
…110001011001000101001
321010120002011100102020220
4131103321132023020221
5231000120403144431
64141154034040253
7265344333424116
oct35237136131051
97116064312226
102014230131241
11707259442029
12286455719089
13117c3074a183
146d6bc74d90d
15375dc41cb96
hex1d4f978b229

2014230131241 has 4 divisors (see below), whose sum is σ = 2685640174992. Its totient is φ = 1342820087492.

The previous prime is 2014230131237. The next prime is 2014230131351. The reversal of 2014230131241 is 1421310324102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2014230131241 - 22 = 2014230131237 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2014230131201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335705021871 + ... + 335705021876.

It is an arithmetic number, because the mean of its divisors is an integer number (671410043748).

Almost surely, 22014230131241 is an apocalyptic number.

It is an amenable number.

2014230131241 is a deficient number, since it is larger than the sum of its proper divisors (671410043751).

2014230131241 is an equidigital number, since it uses as much as digits as its factorization.

2014230131241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671410043750.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 2014230131241 its reverse (1421310324102), we get a palindrome (3435540455343).

The spelling of 2014230131241 in words is "two trillion, fourteen billion, two hundred thirty million, one hundred thirty-one thousand, two hundred forty-one".

Divisors: 1 3 671410043747 2014230131241