Base | Representation |
---|---|
bin | 11101010100000000110… |
… | …111100000000011001111 |
3 | 21010120101210211022201101 |
4 | 131110000313200003033 |
5 | 231000344134223043 |
6 | 4141214225323531 |
7 | 265350401166550 |
oct | 35240067400317 |
9 | 7116353738641 |
10 | 2014354211023 |
11 | 707312490000 |
12 | 28648b1965a7 |
13 | 117c5037206b |
14 | 6d6d100c327 |
15 | 375e827c24d |
hex | 1d500de00cf |
2014354211023 has 40 divisors (see below), whose sum is σ = 2575243612800. Its totient is φ = 1543018184400.
The previous prime is 2014354211021. The next prime is 2014354211101. The reversal of 2014354211023 is 3201124534102.
It is not a de Polignac number, because 2014354211023 - 21 = 2014354211021 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2014354210982 and 2014354211000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2014354211021) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 5880168 + ... + 6213298.
It is an arithmetic number, because the mean of its divisors is an integer number (64381090320).
Almost surely, 22014354211023 is an apocalyptic number.
2014354211023 is a deficient number, since it is larger than the sum of its proper divisors (560889401777).
2014354211023 is an frugal number, since it uses more digits than its factorization.
2014354211023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 333241 (or 333208 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 2014354211023 its reverse (3201124534102), we get a palindrome (5215478745125).
The spelling of 2014354211023 in words is "two trillion, fourteen billion, three hundred fifty-four million, two hundred eleven thousand, twenty-three".
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