Base | Representation |
---|---|
bin | 11101010100000100010… |
… | …001011100010111001111 |
3 | 21010120112210022221111001 |
4 | 131110010101130113033 |
5 | 231001003300441221 |
6 | 4141224030041131 |
7 | 265351663621153 |
oct | 35240421342717 |
9 | 7116483287431 |
10 | 2014411343311 |
11 | 707341762374 |
12 | 2864a63491a7 |
13 | 117c5c156953 |
14 | 6d6d8841063 |
15 | 375ed2b5391 |
hex | 1d50445c5cf |
2014411343311 has 4 divisors (see below), whose sum is σ = 2014650621400. Its totient is φ = 2014172065224.
The previous prime is 2014411343297. The next prime is 2014411343353. The reversal of 2014411343311 is 1133431144102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2014411343311 - 25 = 2014411343279 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2014411343311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2014411343381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119626416 + ... + 119643253.
It is an arithmetic number, because the mean of its divisors is an integer number (503662655350).
Almost surely, 22014411343311 is an apocalyptic number.
2014411343311 is a deficient number, since it is larger than the sum of its proper divisors (239278089).
2014411343311 is an equidigital number, since it uses as much as digits as its factorization.
2014411343311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239278088.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 2014411343311 its reverse (1133431144102), we get a palindrome (3147842487413).
The spelling of 2014411343311 in words is "two trillion, fourteen billion, four hundred eleven million, three hundred forty-three thousand, three hundred eleven".
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