Base | Representation |
---|---|
bin | 1011101110101100000… |
… | …0000000010000101010 |
3 | 201021010122202200020000 |
4 | 2323223000000100222 |
5 | 11300143323024232 |
6 | 232323431043430 |
7 | 20362430310051 |
oct | 2735300002052 |
9 | 637118680200 |
10 | 201511142442 |
11 | 78507871955 |
12 | 33079810576 |
13 | 16005412cbc |
14 | 9a78a85398 |
15 | 5395e7027c |
hex | 2eeb00042a |
201511142442 has 20 divisors (see below), whose sum is σ = 451534226946. Its totient is φ = 67170380760.
The previous prime is 201511142401. The next prime is 201511142447. The reversal of 201511142442 is 244241115102.
201511142442 is a `hidden beast` number, since 2 + 0 + 1 + 511 + 142 + 4 + 4 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 157879870281 + 43631272161 = 397341^2 + 208881^2 .
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (201511142447) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 621947809 + ... + 621948132.
Almost surely, 2201511142442 is an apocalyptic number.
201511142442 is an abundant number, since it is smaller than the sum of its proper divisors (250023084504).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201511142442 is a wasteful number, since it uses less digits than its factorization.
201511142442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1243895955 (or 1243895946 counting only the distinct ones).
The product of its (nonzero) digits is 2560, while the sum is 27.
Adding to 201511142442 its reverse (244241115102), we get a palindrome (445752257544).
The spelling of 201511142442 in words is "two hundred one billion, five hundred eleven million, one hundred forty-two thousand, four hundred forty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •