Base | Representation |
---|---|
bin | 10010110001000110… |
… | …011111111010101011 |
3 | 1221000100220222100221 |
4 | 102301012133322223 |
5 | 312232142440021 |
6 | 13131324510511 |
7 | 1312235602222 |
oct | 226106377253 |
9 | 57010828327 |
10 | 20151140011 |
11 | 860087a822 |
12 | 3aa46ab437 |
13 | 1b91ab56b2 |
14 | d923c9cb9 |
15 | 7ce173241 |
hex | 4b119feab |
20151140011 has 4 divisors (see below), whose sum is σ = 20156952400. Its totient is φ = 20145327624.
The previous prime is 20151139933. The next prime is 20151140027. The reversal of 20151140011 is 11004115102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11004115102 = 2 ⋅5502057551.
It is a cyclic number.
It is not a de Polignac number, because 20151140011 - 223 = 20142751403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20151143011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2900991 + ... + 2907928.
It is an arithmetic number, because the mean of its divisors is an integer number (5039238100).
Almost surely, 220151140011 is an apocalyptic number.
20151140011 is a deficient number, since it is larger than the sum of its proper divisors (5812389).
20151140011 is an equidigital number, since it uses as much as digits as its factorization.
20151140011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5812388.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 20151140011 its reverse (11004115102), we get a palindrome (31155255113).
The spelling of 20151140011 in words is "twenty billion, one hundred fifty-one million, one hundred forty thousand, eleven".
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