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201520023 = 31719207967
BaseRepresentation
bin11000000001011…
…11001110010111
3112001012021111120
430000233032113
5403042120043
631555135023
74664614635
oct1400571627
9461167446
10201520023
11a3830a81
12575a4473
133299a123
141ca9a355
1512a59983
hexc02f397

201520023 has 16 divisors (see below), whose sum is σ = 299473920. Its totient is φ = 119788416.

The previous prime is 201520021. The next prime is 201520031. The reversal of 201520023 is 320025102.

201520023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 201520023 - 21 = 201520021 is a prime.

It is a super-2 number, since 2×2015200232 = 81220639339841058, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201519984 and 201520011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201520021) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103015 + ... + 104952.

It is an arithmetic number, because the mean of its divisors is an integer number (18717120).

Almost surely, 2201520023 is an apocalyptic number.

201520023 is a deficient number, since it is larger than the sum of its proper divisors (97953897).

201520023 is a wasteful number, since it uses less digits than its factorization.

201520023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 208006.

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 201520023 is about 14195.7748291525. The cubic root of 201520023 is about 586.2813348954.

Adding to 201520023 its reverse (320025102), we get a palindrome (521545125).

The spelling of 201520023 in words is "two hundred one million, five hundred twenty thousand, twenty-three".

Divisors: 1 3 17 19 51 57 323 969 207967 623901 3535439 3951373 10606317 11854119 67173341 201520023