Search a number
-
+
201520213 = 1975714011
BaseRepresentation
bin11000000001011…
…11010001010101
3112001012021202121
430000233101111
5403042121323
631555135541
74664615326
oct1400572125
9461167677
10201520213
11a3831134
12575a45b1
133299a23b
141ca9a44d
1512a59a5d
hexc02f455

201520213 has 8 divisors (see below), whose sum is σ = 212421920. Its totient is φ = 190648080.

The previous prime is 201520199. The next prime is 201520219. The reversal of 201520213 is 312025102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201520213 - 213 = 201512021 is a prime.

It is a super-2 number, since 2×2015202132 = 81220792495130738, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201520219) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7378 + ... + 21388.

It is an arithmetic number, because the mean of its divisors is an integer number (26552740).

Almost surely, 2201520213 is an apocalyptic number.

It is an amenable number.

201520213 is a deficient number, since it is larger than the sum of its proper divisors (10901707).

201520213 is a wasteful number, since it uses less digits than its factorization.

201520213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14787.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 201520213 is about 14195.7815212830. The cubic root of 201520213 is about 586.2815191507.

Adding to 201520213 its reverse (312025102), we get a palindrome (513545315).

The spelling of 201520213 in words is "two hundred one million, five hundred twenty thousand, two hundred thirteen".

Divisors: 1 19 757 14011 14383 266209 10606327 201520213