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20152023 = 36717341
BaseRepresentation
bin100110011011…
…1111011010111
31101220211101020
41030313323113
520124331043
61555532223
7333201153
oct114677327
941824336
1020152023
1110414571
1268ba073
134237698
142968063
151b80e83
hex1337ed7

20152023 has 4 divisors (see below), whose sum is σ = 26869368. Its totient is φ = 13434680.

The previous prime is 20152019. The next prime is 20152039. The reversal of 20152023 is 32025102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20152023 - 22 = 20152019 is a prime.

It is a super-2 number, since 2×201520232 = 812208061985058, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20151993 and 20152011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20152063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3358668 + ... + 3358673.

It is an arithmetic number, because the mean of its divisors is an integer number (6717342).

Almost surely, 220152023 is an apocalyptic number.

20152023 is a deficient number, since it is larger than the sum of its proper divisors (6717345).

20152023 is an equidigital number, since it uses as much as digits as its factorization.

20152023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6717344.

The product of its (nonzero) digits is 120, while the sum is 15.

The square root of 20152023 is about 4489.1004666859. The cubic root of 20152023 is about 272.1277829165.

Adding to 20152023 its reverse (32025102), we get a palindrome (52177125).

The spelling of 20152023 in words is "twenty million, one hundred fifty-two thousand, twenty-three".

Divisors: 1 3 6717341 20152023