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20152423055 = 519212130769
BaseRepresentation
bin10010110001001011…
…011001001010001111
31221000110100011101002
4102301023121022033
5312233010014210
613131412210515
71312252524662
oct226113311217
957013304332
1020152423055
118601576796
123aa5009a3b
131b921446ab
14d926416d9
157ce3284a5
hex4b12d928f

20152423055 has 8 divisors (see below), whose sum is σ = 25455692400. Its totient is φ = 15273415296.

The previous prime is 20152422971. The next prime is 20152423069. The reversal of 20152423055 is 55032425102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20152423055 - 218 = 20152160911 is a prime.

It is a super-2 number, since 2×201524230552 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 106065290 + ... + 106065479.

It is an arithmetic number, because the mean of its divisors is an integer number (3181961550).

Almost surely, 220152423055 is an apocalyptic number.

20152423055 is a deficient number, since it is larger than the sum of its proper divisors (5303269345).

20152423055 is a wasteful number, since it uses less digits than its factorization.

20152423055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212130793.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 20152423055 its reverse (55032425102), we get a palindrome (75184848157).

The spelling of 20152423055 in words is "twenty billion, one hundred fifty-two million, four hundred twenty-three thousand, fifty-five".

Divisors: 1 5 19 95 212130769 1060653845 4030484611 20152423055