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20153000414363 = 43468674428241
BaseRepresentation
bin1001001010100001111000…
…11011100100110010011011
32122100121102020201212021012
410211100330123210302123
510120141321101224423
6110510054404004135
74150002065052605
oct445207433446233
978317366655235
1020153000414363
11646a926389983
12231595309064b
13b3255c3611bb
144d95a62c2175
1524e35c08c078
hex12543c6e4c9b

20153000414363 has 4 divisors (see below), whose sum is σ = 20621674842648. Its totient is φ = 19684325986080.

The previous prime is 20153000414317. The next prime is 20153000414381. The reversal of 20153000414363 is 36341400035102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20153000414363 - 216 = 20153000348827 is a prime.

It is a super-2 number, since 2×201530004143632 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20153000434363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 234337214078 + ... + 234337214163.

It is an arithmetic number, because the mean of its divisors is an integer number (5155418710662).

Almost surely, 220153000414363 is an apocalyptic number.

20153000414363 is a deficient number, since it is larger than the sum of its proper divisors (468674428285).

20153000414363 is an equidigital number, since it uses as much as digits as its factorization.

20153000414363 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 468674428284.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 20153000414363 its reverse (36341400035102), we get a palindrome (56494400449465).

The spelling of 20153000414363 in words is "twenty trillion, one hundred fifty-three billion, four hundred fourteen thousand, three hundred sixty-three".

Divisors: 1 43 468674428241 20153000414363