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201530014543 = 11131409300801
BaseRepresentation
bin1011101110110000011…
…1111111101101001111
3201021011222021110212201
42323230013333231033
511300213140431133
6232325343342331
720363046600544
oct2735407775517
9637158243781
10201530014543
1178517491830
1233083bb19a7
13160092bcc20
149a7b398bcb
15539794bd7d
hex2eec1ffb4f

201530014543 has 8 divisors (see below), whose sum is σ = 236762534736. Its totient is φ = 169116096000.

The previous prime is 201530014471. The next prime is 201530014561. The reversal of 201530014543 is 345410035102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201530014543 - 29 = 201530014031 is a prime.

It is a super-2 number, since 2×2015300145432 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201530014573) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 704650258 + ... + 704650543.

It is an arithmetic number, because the mean of its divisors is an integer number (29595316842).

Almost surely, 2201530014543 is an apocalyptic number.

201530014543 is a deficient number, since it is larger than the sum of its proper divisors (35232520193).

201530014543 is a wasteful number, since it uses less digits than its factorization.

201530014543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1409300825.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 201530014543 its reverse (345410035102), we get a palindrome (546940049645).

The spelling of 201530014543 in words is "two hundred one billion, five hundred thirty million, fourteen thousand, five hundred forty-three".

Divisors: 1 11 13 143 1409300801 15502308811 18320910413 201530014543