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20154210313 = 83242821811
BaseRepresentation
bin10010110001010010…
…001101100000001001
31221000120200222000211
4102301102031200021
5312233434212223
613131514401121
71312303650436
oct226122154011
957016628024
1020154210313
118602587566
123aa57301a1
131b9261c043
14d92988b8d
157ce57cd0d
hex4b148d809

20154210313 has 4 divisors (see below), whose sum is σ = 20397032208. Its totient is φ = 19911388420.

The previous prime is 20154210269. The next prime is 20154210317. The reversal of 20154210313 is 31301245102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20154210313 - 221 = 20152113161 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20154210317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121410823 + ... + 121410988.

It is an arithmetic number, because the mean of its divisors is an integer number (5099258052).

Almost surely, 220154210313 is an apocalyptic number.

It is an amenable number.

20154210313 is a deficient number, since it is larger than the sum of its proper divisors (242821895).

20154210313 is an equidigital number, since it uses as much as digits as its factorization.

20154210313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 242821894.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 20154210313 its reverse (31301245102), we get a palindrome (51455455415).

The spelling of 20154210313 in words is "twenty billion, one hundred fifty-four million, two hundred ten thousand, three hundred thirteen".

Divisors: 1 83 242821811 20154210313