Base | Representation |
---|---|
bin | 10010110001010010… |
… | …001101110011100011 |
3 | 1221000120201000201211 |
4 | 102301102031303203 |
5 | 312233434232210 |
6 | 13131514410551 |
7 | 1312303654162 |
oct | 226122156343 |
9 | 57016630654 |
10 | 20154211555 |
11 | 8602588495 |
12 | 3aa5730a57 |
13 | 1b9261c78a |
14 | d929893d9 |
15 | 7ce57d38a |
hex | 4b148dce3 |
20154211555 has 16 divisors (see below), whose sum is σ = 24408576000. Its totient is φ = 15975036000.
The previous prime is 20154211547. The next prime is 20154211559. The reversal of 20154211555 is 55511245102.
It is not a de Polignac number, because 20154211555 - 23 = 20154211547 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20154211559) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 195430 + ... + 280180.
It is an arithmetic number, because the mean of its divisors is an integer number (1525536000).
Almost surely, 220154211555 is an apocalyptic number.
20154211555 is a deficient number, since it is larger than the sum of its proper divisors (4254364445).
20154211555 is a wasteful number, since it uses less digits than its factorization.
20154211555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85194.
The product of its (nonzero) digits is 10000, while the sum is 31.
Adding to 20154211555 its reverse (55511245102), we get a palindrome (75665456657).
The spelling of 20154211555 in words is "twenty billion, one hundred fifty-four million, two hundred eleven thousand, five hundred fifty-five".
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