20154264331 has 4 divisors (see below), whose sum is σ = 20289528000. Its totient is φ = 20019000664.

The previous prime is 20154264323. The next prime is 20154264353. The reversal of 20154264331 is 13346245102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13346245102 = 2 ⋅6673122551.

It is a cyclic number.

It is not a de Polignac number, because 20154264331 - 2³ = 20154264323 is a prime.

It is a super-2 number, since 2×20154264331² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20154264293 and 20154264302.

It is not an unprimeable number, because it can be changed into a prime (20154264301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67631611 + ... + 67631908.

It is an arithmetic number, because the mean of its divisors is an integer number (5072382000).

Almost surely, 2^20154264331 is an apocalyptic number.

20154264331 is a deficient number, since it is larger than the sum of its proper divisors (135263669).

20154264331 is a wasteful number, since it uses less digits than its factorization.

20154264331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135263668.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 20154264331 in words is "twenty billion, one hundred fifty-four million, two hundred sixty-four thousand, three hundred thirty-one".