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20154313531 = 1110916809269
BaseRepresentation
bin10010110001010010…
…100110101100111011
31221000120220012121201
4102301102212230323
5312234001013111
613131520515031
71312304560402
oct226122465473
957016805551
1020154313531
118602648070
123aa577ba77
131b92657011
14d929b4639
157ce59d6c1
hex4b14a6b3b

20154313531 has 8 divisors (see below), whose sum is σ = 22188236400. Its totient is φ = 18154009440.

The previous prime is 20154313511. The next prime is 20154313561. The reversal of 20154313531 is 13531345102.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20154313531 - 25 = 20154313499 is a prime.

It is a super-2 number, since 2×201543135312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20154313531.

It is not an unprimeable number, because it can be changed into a prime (20154313511) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8403436 + ... + 8405833.

It is an arithmetic number, because the mean of its divisors is an integer number (2773529550).

Almost surely, 220154313531 is an apocalyptic number.

20154313531 is a deficient number, since it is larger than the sum of its proper divisors (2033922869).

20154313531 is a wasteful number, since it uses less digits than its factorization.

20154313531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16809389.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 20154313531 its reverse (13531345102), we get a palindrome (33685658633).

The spelling of 20154313531 in words is "twenty billion, one hundred fifty-four million, three hundred thirteen thousand, five hundred thirty-one".

Divisors: 1 11 109 1199 16809269 184901959 1832210321 20154313531