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20154324420713 = 72879189202959
BaseRepresentation
bin1001001010100100010110…
…10110010000100001101001
32122100201211112002100112102
410211102023112100201221
510120202024022430323
6110510434022023145
74150046642656460
oct445221326204151
978321745070472
1020154324420713
1164704457934aa
122316062577ab5
13b32710753002
144d96900919d7
1524e3d8420328
hex12548b590869

20154324420713 has 4 divisors (see below), whose sum is σ = 23033513623680. Its totient is φ = 17275135217748.

The previous prime is 20154324420709. The next prime is 20154324420757. The reversal of 20154324420713 is 31702442345102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20154324420713 - 22 = 20154324420709 is a prime.

It is not an unprimeable number, because it can be changed into a prime (20154324420613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1439594601473 + ... + 1439594601486.

It is an arithmetic number, because the mean of its divisors is an integer number (5758378405920).

Almost surely, 220154324420713 is an apocalyptic number.

It is an amenable number.

20154324420713 is a deficient number, since it is larger than the sum of its proper divisors (2879189202967).

20154324420713 is an equidigital number, since it uses as much as digits as its factorization.

20154324420713 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2879189202966.

The product of its (nonzero) digits is 161280, while the sum is 38.

Adding to 20154324420713 its reverse (31702442345102), we get a palindrome (51856766765815).

The spelling of 20154324420713 in words is "twenty trillion, one hundred fifty-four billion, three hundred twenty-four million, four hundred twenty thousand, seven hundred thirteen".

Divisors: 1 7 2879189202959 20154324420713