Search a number
-
+
2015460142053 = 3671820047351
BaseRepresentation
bin11101010101000010110…
…010010010101111100101
321010200020212211102212220
4131111002302102233211
5231010130244021203
64141520053302553
7265416660354351
oct35250262225745
97120225742786
102015460142053
1170782a786396
12286739634a59
1311809851b517
146d797c52461
15376603d5653
hex1d542c92be5

2015460142053 has 4 divisors (see below), whose sum is σ = 2687280189408. Its totient is φ = 1343640094700.

The previous prime is 2015460142049. The next prime is 2015460142097. The reversal of 2015460142053 is 3502410645102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2015460142053 - 22 = 2015460142049 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2015460142013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335910023673 + ... + 335910023678.

It is an arithmetic number, because the mean of its divisors is an integer number (671820047352).

Almost surely, 22015460142053 is an apocalyptic number.

It is an amenable number.

2015460142053 is a deficient number, since it is larger than the sum of its proper divisors (671820047355).

2015460142053 is an equidigital number, since it uses as much as digits as its factorization.

2015460142053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671820047354.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 2015460142053 its reverse (3502410645102), we get a palindrome (5517870787155).

The spelling of 2015460142053 in words is "two trillion, fifteen billion, four hundred sixty million, one hundred forty-two thousand, fifty-three".

Divisors: 1 3 671820047351 2015460142053