Base | Representation |
---|---|
bin | 1001001010100101101000… |
… | …10111001010110011111111 |
3 | 2122100210121110212200120220 |
4 | 10211102310113022303333 |
5 | 10120204431201302221 |
6 | 110511030202312423 |
7 | 4150102666525356 |
oct | 445226427126377 |
9 | 78323543780526 |
10 | 20155012525311 |
11 | 6470769148694 |
12 | 2316214ab8713 |
13 | b327c0188bb1 |
14 | 4d971761099d |
15 | 24e428a430c6 |
hex | 1254b45cacff |
20155012525311 has 4 divisors (see below), whose sum is σ = 26873350033752. Its totient is φ = 13436675016872.
The previous prime is 20155012525283. The next prime is 20155012525379. The reversal of 20155012525311 is 11352521055102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20155012525311 - 230 = 20153938783487 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20155012525211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3359168754216 + ... + 3359168754221.
It is an arithmetic number, because the mean of its divisors is an integer number (6718337508438).
Almost surely, 220155012525311 is an apocalyptic number.
20155012525311 is a deficient number, since it is larger than the sum of its proper divisors (6718337508441).
20155012525311 is an equidigital number, since it uses as much as digits as its factorization.
20155012525311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6718337508440.
The product of its (nonzero) digits is 15000, while the sum is 33.
The spelling of 20155012525311 in words is "twenty trillion, one hundred fifty-five billion, twelve million, five hundred twenty-five thousand, three hundred eleven".
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